Module 1.8 Divergence of a Vector Field

Module 1.8 Divergence of a Vector Field
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	$ \overrightarrow{\bf {A}} = \left\{ \begin{equation}\begin{aligned} \hat{\bf {a}}_{r} \textit{ρ}_{0} \it r^{n},\quad 0 \le r \lt 1\\ \hat{\bf {a}}_{r} \frac{{ρ}_{0}}{r}, \hspace{1.2cm} r \gt 1 \\ \end{aligned}\end{equation} \right. $ $ \overrightarrow{\bf {A}} = \hat{\bf {a}}_{\varphi} \it r^{n}, \quad n \ge 1$ $\overrightarrow{\bf {A}} = \hat{\bf {a}}_{\textit{x}} \it{xy} - \hat{\bf {a}}_{\textit{y}} \it{2x}$ Cylindrical Coordinates Cartesian Coordinates

$ \overrightarrow{\bf {A}} = \left\{ \begin{equation}\begin{aligned} \hat{\bf {a}}_{r} \textit{ρ}_{0} \it r^{n},\quad 0 \le r \lt 1\\ \hat{\bf {a}}_{r} \frac{{ρ}_{0}}{r}, \hspace{1.2cm} r \gt 1 \\ \end{aligned}\end{equation} \right. $

$ \overrightarrow{\bf {A}} = \hat{\bf {a}}_{\varphi} \it r^{n}, \quad n \ge 1$

$\overrightarrow{\bf {A}} = \hat{\bf {a}}_{\textit{x}} \it{xy} - \hat{\bf {a}}_{\textit{y}} \it{2x}$

Cylindrical Coordinates

Cartesian Coordinates